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The answer is 2. DBC = 68 degrees which means BCA has to also equal 68 degrees because it is an isosceles triangle. ACB and ACD have to equal 90 degrees. So you do 90 - 68 which equals 22 degrees. Therefore, the answer is 2.
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22 degrees
reason. angle cob +angle ocb +68=180
90 +68+ angle ocb =180
ocb=180-158
ocb=22
cob=90; b cos diagonals are perpendicular to each other in a rectangle
reason. angle cob +angle ocb +68=180
90 +68+ angle ocb =180
ocb=180-158
ocb=22
cob=90; b cos diagonals are perpendicular to each other in a rectangle
i want angle ACD
not ocb
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The answer is 2. DBC = 68 degrees which means BCA has to also equal 68 degrees because it is an isosceles triangle. ACB and ACD have to equal 90 degrees because it is a complementary angle. So you do 90 - 68 which equals 22 degrees. Therefore, the answer is 2.
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