Math, asked by kukkalavamsi20p6972f, 1 year ago

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Answered by Rohan079

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Answered by 1Shubhu1

$log(125) - log(625) + log(25) = log(x) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \log(m) - log(n) = log( \frac{m}{n} \\ log( \frac{125}{625} ) + log(25) = log(x) \\ log( \frac{21}{125} ) + log(25) = log(x) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: log( m ) + log(n) = log( \frac{m}{n} ) \\ log( \frac{21}{125 } \times 25 ) = log(x) \\ log(5) = log(x) = > x = 5$

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