Question

Answer with process​

Answer 1

Step-by-step explanation:

Given a,b,c are in A.P.

Dividing each term by abc, we get

⇒ (a/abc),(b/abc),(c/abc) are in A.P

On simplifying, we get

⇒ (1/bc),(1/ac),(1/ab) are in A.P.

Hope it helps!

Answer 2

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step-by-step explanation:

♣ Arithmetic Progression (A.P)

✍️ In mathematics, an arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

✍️ Difference here means the second minus the first.

✍️ For example, the sequence 5, 7, 9, 11, 13, 15.. . is an arithmetic progression with common difference of 2

Now,

Given,

a, b, c are in A.P

To prove :

1/bc, 1/ac, 1/ab are in A.P

Proof:

we know that,

if we divide all the terms of an A.P by a specific number,

then the series formed,

will also be in A.P

so,

dividing the terms with (abc)

we get,

a/abc, b/abc, c/abc are in A.P

or,

1/bc, 1/ac, 1/ab are in A.P

Hence,

proved✍️