Question

Answer with proper instructions. ​

Answer 1

Answer:

Correct option is

A

90

Wt of Ag salt =0.76gm

Wt of Ag after ignition =0.54gm

Eq.wt.ofAg

Eq.wt.ofsilversalt(E)

=

wt.ofAg

wt.ofsilversalt

⇒

108

E

=

0.54

0.76

⇒E=152

Eq. wt. of acid = (Eq. wt. of silver salt) − (Eq. wt. of Ag) +

2

Basicity

=152−108+1=45

∴ Molar mass of acid =45×2=90gm mole

−1