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A current of 2 ampere is produced by battery of 6 cells each of 0.2 V. Find the 'R' and the 'energy' dissipated by 30s.

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Answer 1

Answer:

i=2A

V=0.2×6=1.2V

So as v=ir

1.2=2×r

0.6 ohm=r

Now h=i²rt

So h=2²×o.6×0.5

H=4×0.6×0.5

=1.2 joule

Hope it helps dear..

Answer 2

Explanation:

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