Math, asked by Anonymous, 8 months ago

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Answered by Anonymous
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(A + B)’s 1 day’s work = 1/18

(B + C)’s 1 day’s work = 1/24

(C + A)’s 1 day’s work = 1/36

On adding,

2(A + B + C)’s 1 day’s work = 1/18+1/24+ 1/26 = 4+3+2/72= 1/8

∴ (A + B + C)’s 1 day’s work = 1/16

∴ A, B and C together will complete the work in 16 days.

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