Question

answer with solution correctly ​

Answer 1

Answer:

option d ) 270      is the right answer.

Explanation:

given:

every lamp burns for 10 hrs ( = 36000 sec ) a day

power consumed by 5 lamps in a day = 5 × 60 × 36000

                                                                        = 1.08 × $10^{7}$ J

power consumed by 6 lamps in a day = 6 × 100 × 36000

                                                                        = 2.16 × $10^{7}$ J

total power consumed in a day = 1.08 × $10^{7}$ J +  2.16 × $10^{7}$ J

                                                    = 3.24 ×  $10^{7}$ J

total power consumed in a month = 3.24 × $10^{7}$ J × 30

                                                        = 97.2 ×  $10^{7}$ J

we know that 1 unit = 1 KWh = 3.6 × $10^{6}$ J

so,

total power consumed in a month = 97.2 ×  $10^{7}$ J / 3.6 × $10^{6}$ J

                                                         = 270 units

if the cost of one unit is ₹ 1 , then cost of 270 units = ₹ 270.

Thus you got the answer.

If you find this useful , mark this answer as the brainliest.