Question

Answer with solution



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Answer 1

ANSWER

∠BEC+∠DEC=180

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(complimentary angles)

130

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+∠DEC=180

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∠DEC=50

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In ΔDEC -

∠DEC+∠ECD+∠CDE=180

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∠CDE=110

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by theorem of circles -

∠BAC=∠CDE

∴∠BAC=110

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Answer 2

AngleBAC=AngleBDC=75
Angles are equal in same segment of a circle
AngleAED+DEC=180
Angle sum property
138+AngleDEC=180
AngleDEC=180-138=42
In triangle EDC
AngleDEC +angleEDC+AngleDCF=180
Angle sum property
AngleDCE=180-117
=63

Angle ECD= 63