Question

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Answer 1

Answer:

Ques 6) Option 1

Ques 7) Option 4

Ques 8) Option 1

Ques 9) Option 3

Ques 10) 1

STEP BY STEP EXPLANATION:

Ques 6)

Area of the circle = 1386 $cm^{2}$

Let the radius be r

ATQ

$\pi r^{2} = 1386$

$r^{2} = \frac{1386 * 7}{22}$

$r^{2} = 63 * 7$

$r = \sqrt{3*3*7*7}$

r = 3 * 7

r = 21 cm

Circumference of the circle = $2\pi r$

  = $2(\frac{22}{7} )(21)$

   = 2 * 22 * 3

    = 132 cm

Ques 7)

Perimeter of the square = 10.8 cm

Let the side of the square be a

ATQ

4a = 10.8

$a = \frac{108}{4 * 10}$

$a = \frac{27}{10}$

Area of the square = $a^{2}$

    = $( \frac{27}{10})^{2}$

    = $\frac{729}{100}$

    = 7.29 $cm^{2}$

Ques 8)

Radius of the cylinder = r = 7 cm

Height of the cylinder = h = 15 cm

Total surface are of the cylinder = $2\pi r( r + h)$

   =  $2(\frac{22}{7} )7( 7 + 15)$

   =  $2(22)( 7 + 15)$

   = 2(22)(22)

   = 968 $cm^{2}$

Ques 9)

$5^{2} =4^{2} + 3^{2} \\25 = 16 + 9\\25 = 25$

Ques 10)

Let the sides of the right angled isosceles triangle be a , b , c

Its is given that it is an isosceles triangle which means its base and perpendicular will be equal therefore a = b

ATQ

a = b = 20 cm

Area of the triangle = $(\frac{1}{2} )(a)(b)$

 = $(\frac{1}{2} )(20)(20)$

 = 10 * 20

 = 200 $cm^{2}$

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