Math, asked by nitrogenngel5, 3 months ago

ANSWER WITH STEPS AND I WILL GIVE YOU BRAINLILIEST AND GIVE THANKS Construct a right-angled triangle PQR right angled at P such that PQ=6cm and
PR= 8 cm.

Answers

Answered by KapilShekhawat
1

Answer:

step:1.construct a right triangle PQR and right angle at P.

step:2.i.e. angle P =90°

step:3.PQ =6cm, perpendicular of right triangle PQR and PR=8cm,base of right triangle PQR

step:4.using Pythagoras theorem,

(H)^2=(P)^2+(B)^2

H^2=(6)^2+(8)^2

H^2=36+64

H^2=100

H=√100

H=10

hope it helps!

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