Answer with steps by step
Attachments:
Answers
Answered by
3
Let father’s age be x years and let that of the son be y years.
Now, x+y=45
and,(x-5)(y-5)=34
So,xy -5x-5y+25=34
xy-5(x+y)+25=34
xy-5(45)+25=34
xy-225+25=34
xy=34–25+225
xy=9+225
xy=234
Now, x+y=45 and xy=234
and, 234’s factors are 1,2,3,6,9,13,18,26,39,78,117,234.
We need to find two factors which when added give 45 and when multiplied, give 234.
Clearly, 39 and 6 are two such numbers. { 39+6=45 and 39 x 6=234}
So, x=39 and y=6
So your answer is option B
Hope Helps
pls mark brainliest.
happysingh2160:
why you have take (x-5)(y-5)=34. It should be (x-5)(y-5)=124
his father 's present age be 45-x years
1) Son = X
Father = 45 - X
5years ago Son = ( X -5)
Father = 45 - X - 5 = ( 40 - X)
( X -5) ( 40- X ) = 4 ( 40 - X)
X- 5 = 4
X = 9
ANSWER Son 9 years Father = 36
CHECK
5 years ago product of ages 4 X 31 = 124
4 X fathers age 4 X 31 = 124
Similar questions