Question

Answer with steps ,
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class 11th, ( NLM )​

Answer 1

Since the two blocks always remain in contact with each other, they msut move with the same acceleration.

Using Newton's second law, we get

For block m1:F−N=m1a

For block m2:N=m2a

On adding the two equations, we get

f=(m1+m2)a⇒a=Fm1+m2

Substituting the value of a in (ii), we get

N=m2a=Fm2m1+m2

Answer 2

Answer:

Since the two blocks always remain in contact with each other, they msut move with the same acceleration.

Using Newton's second law, we get

For block m1:F−N=m1a

For block m2:N=m2a

On adding the two equations, we get

f=(m1+m2)a⇒a=Fm1+m2

Substituting the value of a in (ii), we get

N=m2a=Fm2m1+m2

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