Question

answer with steps plz

q.the 5th term of arithametic sequence
is 38 and 9th term is 66what is its 25 term?​

Answer 1

Answer:

GIVEN,

5TH TERM IS 38 = a+4d=38

9TH TERM IS 66 = a+8d=66

Step-by-step explanation:

a+4d=38

a+8d=66

+a -a get cancel

4d - 8d = -4d

38-66 = -28

-4d = -28

d= -28/-4= 7.

let's the value of a is

take one of equation taken,

a+4d=38

a+4(7)=38

a+28= 38

a= 38-28=10

formulae for 25th term

=> a n = a+(n-1)d

a n = 10 + 24×7

a n = 10 + 168

=> 178 //.

HOPE I HAVE DONE RIGHT

Answer 2

Step-by-step explanation:

Given that,

a5=38

b9=66

we can write these terms as

a5-a+4d=38 (1)

a9-a+8d=66 (2)

Now, subtract the equation (1) &(2), we get

-4d= -28

4d=28

d=7

Now, substitute the value of d in (1)

a +4(7)=38

a+28=38

a=38-28=10

To find the value of 25th term,

an=a+(n-1)d

a=10

d=7

n=25