Math, asked by tulsi1850, 11 months ago

Answer with steps plzz

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Answered by Nikunjsingla

1

Answer:

a+b+c=11

ab+bc+ac=38

find a2+b2+c2

Identity- [a+b+c]sq=a2+b2+c2+2(ab+bc+ac)

(11)sq=a2+b2+c2+2(38)

121=a2+b2+c2+76

121-76=a2+b2+c2

45=a2+b2+c2

Hence proved

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