Question

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Answer 1

AB= 6.3... Given

Therefore, Let PQ be 'x'

PQ : AB = 4:3

x/6.3 = 4/3

3x = 6.3×4

3x = 25.2

x = 25.2÷3

x= 8.4

Therefore, measure of PQ = 8.4

∆ABC~∆PQR

angle A = angle P, angle B = Q and angle C= R

Corresponding sides of given triangles

AB/PQ = BC/QR = AC/PR

By putting values of given sides,

6.3/8.4 = 7.2/QR = 5.1/PR

6.3× QR = 8.4× 7.2

6.3 × QR = 60.48

QR = 9.6

7.2 × PR = 9.6 × 5.1

PR = 48.96÷7.2

PR = 6.8

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So, construct the triangle of the following measures,

In ∆ABC,

seg AB= 6.3 cm

seg BC = 7.2 cm

seg AC = 5.1 cm

In ∆ PQR,

seg PQ = 8.4 cm

seg QR = 9.6 cm

seg PR = 6.8 cm

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