Question

answer x2 + 4x – 5 = 0

Answer 1

• Answer :-

→ x² + 4x - 5 = 0

→ x² + 5x - x - 5 = 0

→ x(x + 5) - 1(x + 5) = 0

→ (x + 5)(x - 1) = 0

• x = - 5 and x = 1

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Answer 2

Explanation:

$\large \pink {\tt {{x}^{2} + 4x - 5 = 0}}$

$\large \purple {\tt {or, \: {x}^{2} + 5x - x - 5 = 0}}$

By solving LHS, we get

$\large \pink {\tt {= x(x + 5) - 1(x + 5)}}$

$\large \purple {\tt {= (x - 1)(x + 5)}}$

Answer:

$\large \pink {\tt {{x}^{2} + 4x - 5 = (x-1)(x+5)}}$