Question

answered Abc -3abc =(1/2abc)+(2a+2b +2c+2ab +2bc +2ca ) Prove that LHS=RHS

Answer 1

• All Factors of 540: 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 27, 30, 36, 45, 54, 60, 90, 108, 135, 180, 270 and 540.
• All Factors of 540: 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 27, 30, 36, 45, 54, 60, 90, 108, 135, 180, 270 and 540.Prime Factors of 540: 2, 3, 5.
• All Factors of 540: 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 27, 30, 36, 45, 54, 60, 90, 108, 135, 180, 270 and 540.Prime Factors of 540: 2, 3, 5.Prime Factorization of 540: 22 × 33 × 51
• All Factors of 540: 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 27, 30, 36, 45, 54, 60, 90, 108, 135, 180, 270 and 540.Prime Factors of 540: 2, 3, 5.Prime Factorization of 540: 22 × 33 × 51Sum of Factors of 540: 1680.

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Answer 2

Answer:

Consider, a^2 + b^2 + c^2 – ab – bc – ca = 0

Multiply both sides with 2, we get

2( a^2 + b^2 + c^2 – ab – bc – ca) = 0

⇒ 2a^2 + 2b^2 + 2c^2 – 2ab – 2bc – 2ca = 0

⇒ (a^2 – 2ab + b^2) + (b^2 – 2bc + c^2) + (c^2 – 2ca + a^2) = 0

⇒ (a –b)^2 + (b – c)^2 + (c – a)^2 =0

Here the sum of the terms is a non-negative term which means all the individuals are also positive.

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