answered person is brilliant
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Gokul02:
It's a basic question
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Answered by
2
an=184
a+(n-1)d=184
7+(n-1)×3=184
(n-1)=(184-7)/3
n-1=177/3
n=59+1
n=60
now
a7=184+(7-1)×-3
=184+6×-3
=184-18
=166
hope this will be helpful :-)
a+(n-1)d=184
7+(n-1)×3=184
(n-1)=(184-7)/3
n-1=177/3
n=59+1
n=60
now
a7=184+(7-1)×-3
=184+6×-3
=184-18
=166
hope this will be helpful :-)
Answered by
0
Hey ,Here's ur answer ,
In the given A.P,
t1 (a)=7
t2=10
t3=13
tn=184,
d (common difference)
=t2-t1
=10-7
=3
Using the formula ,
tn=a+(n-1)d
184=7+(n-1)3----------{substituting the values of tn ,a and d}---------
184=7+3n-3
184=3n+4
184-4=3n
180=3n
n=180÷3
n=60
The seven term of an A.p,
tn=a+(n-1)d
t7
=7+(7-1)3
=7+6×3
=7+18
=25
seventh term of A.p is 25
Hopeit helps you!
In the given A.P,
t1 (a)=7
t2=10
t3=13
tn=184,
d (common difference)
=t2-t1
=10-7
=3
Using the formula ,
tn=a+(n-1)d
184=7+(n-1)3----------{substituting the values of tn ,a and d}---------
184=7+3n-3
184=3n+4
184-4=3n
180=3n
n=180÷3
n=60
The seven term of an A.p,
tn=a+(n-1)d
t7
=7+(7-1)3
=7+6×3
=7+18
=25
seventh term of A.p is 25
Hopeit helps you!
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