Question

Answered
the perimeter of a school volleyball court is 177 ft and the length is twice the wide what are the dimensions of the volley ball court?.

Answer 1

✬ Length = 59 ft ✬

✬ Width = 29.5 ft ✬

Step-by-step explanation:

Given:

• Perimeter of volleyball court is 177 ft.
• Length of court is twice the width.

To Find:

• What are the dimensions of court ?

Solution: Let the width of court be x ft. Therefore,

➟ Length of court = 2 times of x

➟ Length = 2x

As we know that

★ Perimeter of Rectangle = 2(Length + Width) ★

A/q

• Perimeter of court is 177 ft.

$\implies{\rm }$ 177 = 2(Length + Width)

$\implies{\rm }$ 177 = 2(2x + x)

$\implies{\rm }$ 177 = 2(3x)

$\implies{\rm }$ 177 = 6x

$\implies{\rm }$ 177/6 = x

$\implies{\rm }$ 29.5 = x

So, measure of

➧ Width of court is x = 29.5 ft.

➧ Length of court is 2x = 2(29.5) = 59 ft.

___________________

★ Verification ★

➧ 2(Length + Width) = 177

➧ 2(59 + 29.5) = 177

➧ 2(88.5) = 177

➧ 177 ft = 177 ft

$\large\bold{\texttt {Verified }}$

Answer 2

ᎯᏁᏕᏯᎬᏒ

Let the Breadth (b) be x foot.

Therefore Length (l) = 2x feet

Perimeter of volleyball court = 177 feet.

Perimeter of rectangular court = 2(l+b)

177 = 2(2x+x)

⇢177 = 2(3x)

⇢177 = 6x

⇢177/6 = x

⇢x = 29.5 feet

∴ Breadth = 29.5 feet

∴ Length = 59 feet