Question

Answering me this question please!!!​

Answer 1

Answer:

51,9

Step-by-step explanation:

Let the divisor be 'n'.

Given that Quotient is 6 more than five times the divisor.

Quotient = 5n + 6.

∴ Dividend = Divisor * Quotient + Remainder

⇒ 460 = n(5n + 6) + 1

⇒ 460 = 5n² + 6n + 1

⇒ 5n² + 6n - 459 = 0

⇒ 5n² - 45n + 51n - 459 = 0

⇒ 5n(n - 9) + 51(n - 9) = 0

⇒ (5n + 51)(n - 9) = 0

⇒ n = 9, -51/5{∵neglected}

⇒ n = 9.

When n = 9:

Quotient = 5n + 6 = 51.

Therefore:

Quotient = 51, Divisor = 9.

Hope it helps!                

Answer 2

Using Remainder theorem:

460 = Divisor x Quotient + Remainder

Let divisor be D, quotient be Q, and Remainder is given 1

So,

460 = Q.D + 1

Q.D = 459.....(1)

Now we have,

Q = 5D + 6....(2)

Solving (1) and (2) we get

Q = 459/D

Putting this in (2) we get

459/D = 5D + 6

459 = 5D² + 6D

5D² + 6D -459 = 0

5D² - 45D + 51D -459 = 0

5D(D - 9) + 51(D - 9) = 0

(5D + 51)(D - 9) = 0

D = 9 or -51/5

As it is given that divisor is natural number, D will only be 9

Divisor = 9

Quotient = 459/9 = 51