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Answer:
The configuration of Cr is 1s2,2s2,2p6,3s2,3p6,4s2,3d4.
l=1 corresponds to p subshell. in the p subshell, there are 12 electrons. 2p6+3p6.
Similarly for l=2, there are 4 electrons. 3d4.
So, option B is correct.
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0
Explanation:
Your answer is 12 and 5 as per your question asked.
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