Math, asked by premmurugan, 11 months ago

answerr withh explanation!!!​

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Answered by hrn21agmailcom
2

Answer:

2019 ;

Step-by-step explanation:

p = 2r ; 3 ( p + q + r ) = s

now.....sine s is a single digit and a multiple of 3...we can try ..3, 6, and 9....let us check.....

3 ( p + q + r ) = 3

( p + q + r ) = 1 but...p = 2r

2r + q + r = 1

3r + q = 1

this is possible only if....r = 0 & q = 1.....then p = 2(0) = 0 ....hence the number begins with zero!

therefore it's not the case!

then take s = 6 and proceed as above, we get...

3r + q = 2....now this is possible if r = 0 & q = 2 but again p = 2(0) = 0...hence this too not the case.

finally......s = 9 then....

3r + q = 3...this is possible if r = 1 & q = 0 where p = 2 (1) = 2 hence our answer is....

pqrs = 2019

similarly.....the other ... u can try.....

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