answerr withh explanation!!!
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Answer:
2019 ;
Step-by-step explanation:
p = 2r ; 3 ( p + q + r ) = s
now.....sine s is a single digit and a multiple of 3...we can try ..3, 6, and 9....let us check.....
3 ( p + q + r ) = 3
( p + q + r ) = 1 but...p = 2r
2r + q + r = 1
3r + q = 1
this is possible only if....r = 0 & q = 1.....then p = 2(0) = 0 ....hence the number begins with zero!
therefore it's not the case!
then take s = 6 and proceed as above, we get...
3r + q = 2....now this is possible if r = 0 & q = 2 but again p = 2(0) = 0...hence this too not the case.
finally......s = 9 then....
3r + q = 3...this is possible if r = 1 & q = 0 where p = 2 (1) = 2 hence our answer is....
pqrs = 2019
similarly.....the other ... u can try.....
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