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1 | P a g e All the best… Date: 13-04-2020
1. A contractor pays Rs. 20 to a worker for each day and the worker forfeits Rs. 10 for
each day if he is idle. At the end of 60 days, the worker gets Rs. 300. Find for how many
days the worker was idle?
Answers
Answer: 30 days
Step by step explanation:
Let 'x' be the number of days where employee is working and 'y' be the number of days where employee is idle.
Total days: 60
x + y = 60 [eq.1]
Worker gets Rs.20 for each working day and Rs. 10 is deducted.
Total amount: Rs. 300
20x - 10y = 300
=> 2x - y = 30 [eq.2]
Adding [eq.1] and [eq.2],
x + y = 60
+ 2x - y = 30
______________
3x = 90
x = 30
Putting value of x in [eq.1]
x + y = 60
30 + y = 60
y = 30
Thus, as we had to find the number of days when the worker was idle, Answer is 30 days.
Let the number of days for which the worker worked be = x
Let the number of days for which the worker was idle be = y
x + y = 60
=> x = 60 - y __(1)
Money recieved by worker for his work (per day) = Rs. 20
Money lost by worker for not working (per day) = Rs. 10
20x + (-10)y = 300 ___(2)
Solve (2) further:
=> 20x - 10y = 300
Put (1):
=> 20 (60 - y) - 10y = 300
=> 1200 - 20y - 10y = 300
=> 30y = 900
=> y = 30
x = 60 - y = 60 - 30
x = 30
Thus, the worker was idle for 30 days.