Math, asked by shivendra5, 1 year ago

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Answered by Swayze
1
a-b = 3……..(1)

b-c= 5 ………….(2)

On adding eq 1& 2

a-c= 8 …………….(3)

From eq 1
a-b= 3
a= 3+b……………(4)

From eq 2
b-c = 5

b = 5+c…………….(5)


From eq 3

a-c = 8

c= a-8……………(6)

a²+b²+c²-ab-bc-ca (given)

= a²-ab +b²-bc+c²-ca

=a(a-b) + b(b-c)+ c (c-a)

=a(3) + b (5) + c (-8)

[ From eq 1, 2,3]

=3a+5b -8c

3a + 5(5+c) -8(a-8)

[ From eq 5,6]

=3a + 5 (5+a-8) -8a+64. ( c=a-8)

=3a + 25 +5a -40-8a+64

=3a+5a-8a+25-40+64

=8a -8a-15+64

a²+b²+c²-ab-bc-ca = 49...

romanticgirl: nice
romanticgirl: sorry dude I can't bcoz I have not asked the question na
shivendra5: Yes you are brilliant
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