Question

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Answer 1

Answer:

Suppose that√2is rational number

√2=p/q (where p and q whole number and no one common factors in p or q)

(√2)²=(p/q)². {Both side squaring}

2=p²/q²

p²=2q². --equation 1

Again,

Suppose that p=2m

(p)²=(2m)². {Both side squaring}

p²=4m²

2q²=4m². (From the equation 1)

q²=2m². --equation 2

From the equation 1 and 2 we have,

p and q have common factor 2 is present.so,we are wrong and √2 is irrational number.

proved

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Step-by-step explanation: