Question

ANSWERS THE QUESTIONS PLEASE FAST

Answer 1

in this equation, let p be the root.
2p= -2mc/(1-m2)
or, p= -mc/(1-m2)-----1 no
and p^2= (c2-a2)/(1-m2)---2no

now m2c2/(1-m2)^2=(c2-a2)/(1-m2)
or, m2c2/(1-m2)=c2-a2
or,m2c2=(c2-a2 )(1-m2)= c2-m2c2-a2+a2m2
or, c2=a2(1+m2)