Answrs needed in full explanation
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REQUIRED SOLUTION:
ANSWERS:
- -x²-y²-1
- a=0
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SOLUTION 1:
Here in this question we have to add all the three equations. We can add similar terms to simplify this question.
Let's start!
=> (x²-y²-1)+(y²-1-x²)+(1-x²-y²)
Now remove the brackets.
=> x²-y²-1+y²-1-x²+1-x²-y²
Now we have to arrange similar terms.
=> x²-x²-x²-y²+y²-y²-1-1+1
Now we can subtract similar terms.
=> -x²-y²-1
Hence the final answer is -x²-y²-1.
____________________________
SOLUTION 2:
Here in this question we have given a quadratic equation and value of x is given to be 0 and we have to find the value of a.
Let's start!
=> p(x)=2x²+x-a
Now put the value of x to be 0 in this equation.
=> p(0)=2(0)²+(0)-a
We know that whenever a number is multiplied by 0, it will give answer to be 0.
=> 0=-a
[∴ Hence a=0]
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