Question

answwr 4th one please

Answer 1

Canvas required for tent = CSA of tent
=
$\pi \: rl$
$\frac{22}{7} \times 5.6 \times 12$
= 211.2
Since the width of canvas is 4m.
So, length of canvas required = 211.2/4
= 52.8
Hence right option is (c) 52.8
Hope it help.