Question

answwr me its imp plz plz plz plz ... ​

Answer 1

FIRST SUM : (which is to be subtracted from 2nd)

$(3{y}^{2} + 2y - 1) + ( - 2 {y}^{2} + 3y - 5) \\ = 3 {y}^{2} + 2y - 1 - 2 {y}^{2} + 3y - 5 \\ = 3 {y}^{2} - 2 {y}^{2} + 2y + 3y - 1 - 5 \\ = {y}^{2} + 5y - 6$

SECOND SUM :

$(5 {y}^{2} - 6y) + (3 {y}^{2} + 5y - 3) \\ = 5 {y}^{2} - 6y + 3 { {y}^{2} + 5y - 3} \\ = 5 {y}^{2} + 3 {y}^{2} - 6y + 5y - 3 \\ = 8 {y}^{2} - y - 3$

SECOND SUM - FIRST SUM

$(8 {y}^{2} - y - 3) - ( {y}^{2} + 5y - 6) \\ = 8 {y }^{2} - y - 3 - {y}^{2} - 5y + 6 \\ = 8 {y}^{2} - {y}^{2} - y - 5y - 3 + 6 \\ = 7 {y}^{2} - 6y + 3$

This is the answer !!

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Answer 2

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