Question

antaraal 15 - 20 ka parisar kya hoga
​

Answer 1

$Given \: class \: interval \: ( 15 - 20 )$

$Range = upper \: limit - lower \: limit$

$= 20 - 15$

$= 5$

Therefore.,

$\red{ Required \: range } \green { = 5 }$

•••♪

Answer 2

Solution:

Class interval 15 - 20

To find Range

Maximum value - Minimum value

Or,

Upper class limit - Lower class limit

Here,

Upper class limit = 20

Lower class limit = 15

Range = 20 - 15

Range = 5

More:

Formula:

Mode:

No particular formula. Here you have just have to see the number which comes maximum time in the given data.

Mean:

The Arithmetic average of the number of observations of items is called mean.

If there are n observations or items $\sf x_1, \: x_2, \: x_3, \: x_4, \: x_5, \: ......., \: x_n,$ then

$\sf{ \large{ Mean = \dfrac{Sum \: of \: all \: observations \: or \: items }{Total \: number \: of \: observations \: or \: items} }}$

$\sf = \dfrac{x_1 + x_2 + x_3 + x_4 + x_5 + ..... + x_n}{n}$

$\sf = \dfrac{\Sigma x_i}{n}$

Greek letter Σ represents total sum of all the observations.

Median:

The median is the value of its middle term.

For finding mean:

( i ) Arrange the given data in ascending or descending order of their magnitude.

( ii ) Count the total number of observations (n) in the given data.

( iii )

⤀ If n is odd,

$\sf median ={ { \huge(} \dfrac{n + 1}{2}{ \huge)}}^{th} term$

⤀ If n is even,

$\sf median = \dfrac{1}{2} [value \: of \: { \huge(}{\dfrac{n}{2}{ \huge)}}^{th} term + value \: of \: { \huge(} {\dfrac{n}{2} + 1{ \huge)}}^{th} term]$

▬▬▬▬▬▬▬▬▬▬▬▬▬▬