Math, asked by phani1174, 1 year ago

anti derivative of sin2x-4e^3x

Answers

Answered by Anonymous
0
The anti derivative of sin 2x – 4e3x is the function of x whose derivative is sin 2x – 4e3x.



It is known that,

ddx(−12cos2x–43e3x)=sin2x–4e3x

 

Therefore, the anti derivative of (sin 2x – 4e3x) is

(−12cos2x–43e3x)

 
Answered by Anonymous
2

Answer:

Anti derivative of (sin2x-4e^3x) is the function of x whose derivative is sin2x-4e^3x

d/dx (-1/2 cos2x-4/3)=sin2x-4e^3x

Therefore anti derivative of (sin2x-4e^3x) is (-1/2 cos2x-4/3e^3x)

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