Anu Aditya, Rina and Rohan are siblings in a family. They wanted to play a game using playing
cards on a holiday. They kept a well shuffled pack of cards facing down on the table.
Each one decided to pick a card in turns from the pack which is kept facing down and the rules of
the game is as follows:
Anu will win the game if they get a red King or a Jack
Aditya will win the game if they gets a non-ace card
Rina will win the game if they gets neither a king nor a queen
(iv) Rohan will win the game if he gets a face card.
Find the probability of Anu winning?
(it)
21
21
52
(iv)
3
26
(iii)
26
(b) What is the probability of Rina winning?
9
(
(ii)
(iii)
(iv)
13
13
26
(c) If the card picked is a face card who will win?
(1) Anu
(ii) Rina
(iv) Aditya
Sir Rohan
(d) When Aditya picked a card, if he gets a diamond 10, who will win the game?
(ii) Aditya
(i) Rohan
(iii) Anu
(iv) No one
[1]
(c)
What is the probability of Aditya winning?
( (ii)
10
12
13
33
Answers
Given :-
- Anu will win the game if they get a red King or a Jack .
- Aditya will win the game if they gets a non-ace card
- Rina will win the game if they gets neither a king nor a queen .
- Rohan will win the game if he gets a face card.
Answer :-
→ Total cards in pack of cards = 52 .
now,
→ Favourable outcomes of Anu winning = A red king + Jack = 2 + 4 = 6
then,
→ Probability of Anu winning = 6/52 = (3/26) (Ans.a)
and,
→ Favourable outcomes of Rina winning = Neither a king nor a queen = 52 - (4 + 4) = 52 - 8 = 44
then,
→ Probability of Rina winning = 44/52 = (11/13) (Ans.b)
now,
→ if the card picked is a face card Rohan will win .
and,
→ Favourable outcomes of Aditya winning = non ace cards = 52 - 4 = 48
then,
→ Probability of Aditya winning = 48/52 = (12/13) (Ans.d)
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