Math, asked by Vikramjeeth, 2 months ago

Anu earns a profit or 18% by selling an article at a certain price. If she were to sell it for 10.50 more, she would have gained 25%. The original cost price of 12 such articles is

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Answers

Answered by VishnuPriya2801
44

Answer:-

Let the Original CP of one article be Rs. x.

Given:

Profit on selling at a certain price = 18%.

We know that,

SP = CP × (100 + Profit%)/100

So,

⟹ SP of one article = x * (100 + 18)/100

SP of one article = Rs. 118x/100

Also given that,

If it is sold for Rs. 10.50 more, she would have gained 25%.

Now,

The SP of the Article = Rs. (118x/100 + 10.50)

And, Profit = 25%.

So,

⟹ 118x/100 + 10.50 = CP × (100 + Profit%)/100

⟹ (118x + 1050)/100 = x * (100 + 25)/100

⟹ 118x + 1050 = 125x

⟹ 1050 = 125x - 118x

⟹ 1050 = 7x

⟹ 1050/7 = x

⟹ Rs. 150 = x

  • Cost Price of 12 such articles = 12 × x = 12 × 150 = Rs. 1800

Answered by Anonymous
55

Answer:

Given :-

  • Anu earns a profit of 18% by selling an article at a certain price. If she were to sell it for 10.50 more, she would have gained 25%.

To Find :-

  • What is the original cost price of 12 such articles.

Formula Used :-

\clubsuit Selling Price Formula :

\mapsto \sf\boxed{\bold{\pink{SP =\: \bigg(\dfrac{100 + P\%}{100}\bigg) \times CP}}}\\

where,

  • SP = Selling Price
  • P = Profit
  • CP = Cost Price

Solution :-

First, we have to find the selling price or SP of one such articles :

Let,

\mapsto Cost Price of one such articles be y.

Given :

  • Profit = 18%

According to the question by using the formula we get,

\implies \sf Selling\: Price\: of\: one\: such\: articles =\: \bigg(\dfrac{100 + 18}{100}\bigg) \times y\\

\implies \sf Selling\: Price\: of\: one\: such\: articles =\: \bigg(\dfrac{118}{100}\bigg) \times y\\

\implies \sf \bold{\purple{Selling\: Price\: of\: one\: such\: articles =\: \bigg(\dfrac{118y}{100}\bigg)}}\\

Again, we have to find the selling price of an articles :

\mapsto She were to sell it for Rs 10.50 more.

\implies \sf \bold{\purple{Selling\: Price =\: \bigg(\dfrac{118y}{100} + 10.50\bigg)}}\\

Again,

\mapsto Gained or profit = 25%

According to the question by using the formula we get,

\implies \sf y \times \dfrac{100 + 25}{100} =\: \dfrac{118y}{100} + 10.50

\implies \sf y \times \dfrac{125}{100} =\: \dfrac{118y}{100} + \dfrac{1050}{100}\\

\implies \sf \dfrac{125y}{100} =\: \dfrac{118y + 1050}{100}\\

By doing cross multiplication we get,

\implies \sf 12500y =\: 11800y + 105000

\implies \sf 12500y - 11800y + 105000

\implies \sf 700y =\: 105000

\implies \sf y =\: \dfrac{1050\cancel{00}}{7\cancel{00}}

\implies \sf y =\: \dfrac{\cancel{1050}}{\cancel{7}}

\implies \sf\bold{\green{y =\: Rs\: 150}}

Now, we have to find the original cost of price of 12 such articles :

\longrightarrow \sf Original\: cost\: of\: 12\: articles =\: Rs\: 12y

\longrightarrow \sf Original\: cost\: of\: 12\: articles =\: Rs\: 12(150)

\longrightarrow \sf\bold{\red{Original\: cost\: of\: 12\: articles =\: Rs\: 1800}}\\

\therefore The original cost price of 12 such articles is Rs 1800.

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