Anu is four years older than Sunil. 8 years ago, Anu was three times Sunil's age. find the ages of Sunil and Anu.
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Let the age of Sunil be = x years
Then Anu`s age = x+4 years
eight years ago sunil`s age = (x-8) years
eight years ago anu`s age = (x-8) + 4 years
it is also given that the age of Anu WAS 3 times sunil`s age
⇒3(x - 8)
∴x-8 +4 = 3(x - 8)
⇒x-4 = 3x -24
⇒x -3x = -24 + 4
⇒-2x = -20
⇒x = -20/-2
∴x = 10
∴The age of Sunil = x =10 years
Anu`s age = x + 4 = 10 + 4 = 14 years.
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