Math, asked by sanu67, 1 year ago

Anu is four years older than Sunil eight years ago anu was three times sunil's age find the ages of Sunil and Anu

Answers

Answered by Ayushk07
14
Let age of Anu be x
Let age of Sunil be y

y + 4 = x

x - 8 = 3(y - 8)

x - 8 = 3y - 24

x + 16 = 3y

Therefore, on simplification,

x - 3y = -16
x - y = 4

-2y = -20

y = 10

10 + 4 = x
x = 14

Therefore, Age of Sunil is 10
And, Age of Anu is 14
Answered by Anonymous
48
Solutions :-

Let the age of Sunil be x
Anu's age = x + 4

8 years ago, Anu was 3 times Sunil's age.

A/q

⇒(x+4) - 8 = 3(x-8)
⇒ x - 4 = 3x - 24
⇒ x - 3x = -24 + 4
⇒ -2x = -20
⇒ x = -20/-2 = 10

Hence,
Age of Sunil = x = 10 years
Age of Anu = x + 4 = (10 + 4) years = 14 years

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