Anu is four years older than Sunil eight years ago anu was three times sunil's age find the ages of Sunil and Anu
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Answered by
14
Let age of Anu be x
Let age of Sunil be y
y + 4 = x
x - 8 = 3(y - 8)
x - 8 = 3y - 24
x + 16 = 3y
Therefore, on simplification,
x - 3y = -16
x - y = 4
-2y = -20
y = 10
10 + 4 = x
x = 14
Therefore, Age of Sunil is 10
And, Age of Anu is 14
Let age of Sunil be y
y + 4 = x
x - 8 = 3(y - 8)
x - 8 = 3y - 24
x + 16 = 3y
Therefore, on simplification,
x - 3y = -16
x - y = 4
-2y = -20
y = 10
10 + 4 = x
x = 14
Therefore, Age of Sunil is 10
And, Age of Anu is 14
Answered by
48
Solutions :-
Let the age of Sunil be x
Anu's age = x + 4
8 years ago, Anu was 3 times Sunil's age.
A/q
⇒(x+4) - 8 = 3(x-8)
⇒ x - 4 = 3x - 24
⇒ x - 3x = -24 + 4
⇒ -2x = -20
⇒ x = -20/-2 = 10
Hence,
Age of Sunil = x = 10 years
Age of Anu = x + 4 = (10 + 4) years = 14 years
_______________________
✯ @shivamsinghamrajput ✯
Let the age of Sunil be x
Anu's age = x + 4
8 years ago, Anu was 3 times Sunil's age.
A/q
⇒(x+4) - 8 = 3(x-8)
⇒ x - 4 = 3x - 24
⇒ x - 3x = -24 + 4
⇒ -2x = -20
⇒ x = -20/-2 = 10
Hence,
Age of Sunil = x = 10 years
Age of Anu = x + 4 = (10 + 4) years = 14 years
_______________________
✯ @shivamsinghamrajput ✯
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