Question

Anu is twice as old as her brother manu if the difference of their ages be 2 years find the age of anu and manu after 10 years.​

Answer 1

Step-by-step explanation:

Let Anu's age=x

and Manu's age=y

Given:

x=2y

and

x-y=2

2y-y=2

y=2

x=2×2=4

After 10 years their ages will be

Anu's age=10+4=14

Manu's age=10+2=12

Answer 2

$\bold\red{✔ \: \: Question :}$

• Anu is twice as old as her brother Manu, if the difference of their ages be 2 years. Find the age of Anu and Manu after 10 years.

$\bold \red{✔ \: \: Answer :}$

• Age of Anu after 10 years = 14 years

• Age of Manu after 10 years = 12 years.

$\bold \red{✔ \: \: Explanation :}$

Given,

• Anu is twice as old as her brother Manu.

• Difference of ages of Anu and Manu is 2 years.

To Find,

• Anu's age after 10 years?

• Manu's age after 10 years?

Solution,

Let, Manu's present age = x

Therefore, Anu's present age = 2x

According to the question,

(2x - x ) = 2

⟹ x = 2

⟹ Manu's present age = 2 years.

$\therefore$ Anu's present age = 2 × 2 = 4 years

We have to find,

• Anu's age after 10 years?
• & Manu's age after 10 years?

So,

$\bold\purple{ Anu's \: age \: after \: 10 \: years \: = \: 4 + 10 \: = 14 \: years }$

And,

$\bold \purple {Manu's \: age \: after \: 10 years \: = \: 2 + 10 = \: 12 \: years.}$