anu is twice as old as her brother manu. if the difference of their ages be 2 years, find the age of anu & manu after 10 years.
Answers
Present age of anu = 2 × ( Present age of manu ) = 2X years.
Difference of their ages = 2
2X - X = 2
X = 2 years.
Present age of manu = X = 2 years
And,
Present age of anu = 2X = 2 × 2 = 4 years.
After 10 years age of manu = Present age + 10 = 2 + 10 = 12 years.
And,
After 10 years age of Anu = Present age + 10 = 4+10 = 14 years
Let the present age of manu be x years,
Present age of anu = 2 times of age of manu
= 2x years
Given,if the difference of manu's age and anu's age is 2 years.
∴ manu's age - anu's age = 2 years
⇒ 2x - x = 2
⇒ x = 2
Therefore present age of anu = x years
= 2 years
present age of manu = 2x years
= 2( 2 ) years
= 4 years
Hence, age of anu after 10 years = present age + 10 years
= 2 + 10 years
= 12 years
Age of manu after 10 years = present age + 10 yerars
= 4 + 10 years
= 14 years
Thus,
age of anu after 10 years will be 12 years and age of manu after 10 years will be 14 years.