Math, asked by Anonymous, 3 days ago

Anu is twice as old as her brother manu it the difference of their ages be 2 years find the age of anu and manu after 10 years​

Answers

Answered by sethrollins13
236

Given :

  • Anu is twice as old as her brother Manu .
  • Difference of their ages is 2 years .

To Find :

  • Age of Anu and Manu .

Solution :

\longmapsto\tt{Let\:the\:age\:of\:Manu\:be=x}

As Given that Anu is twice as old as her brother Manu . So ,

\longmapsto\tt{Age\:of\:Anu=2x}

A.T.Q :

\longmapsto\tt{2x-x=2}

\longmapsto\tt\bf{x=2}

Value of x is 2 .

Therefore :

\longmapsto\tt{Present\:Age\:of\:Anu=2(2)}

\longmapsto\tt\bf{4\:yrs}

\longmapsto\tt{Present\:Age\:of\:Manu=x}

\longmapsto\tt\bf{2\:yrs}

After 10 years :

\longmapsto\tt{Age\:of\:Anu=4+10}

\longmapsto\tt\bf{14\:yrs}

\longmapsto\tt{Age\:of\:Manu=2+10}

\longmapsto\tt\bf{12\:yrs}

Answered by ᎮѕуcнσAεѕтнεтíc
137

✪Given:-

  • Anu is twice old as her brother manu
  • Difference of their ages is 2 years

✪To Find:-

The age of Anu and Manu after 10 years

✪Solution:-

According to the given condition:-

Let the age of Manu be x

and the age of Anu be 2x

✪Now ATQ:-

 \blue \leadsto \bf 2x - x = 2

 \blue \leadsto \bf x = 2

Here we got the value of x as 2.

Hence:-

Present age of Manu x = 2 years

Present age of Anu 2x = 2(2) = 4 years

After 10 years:-

Age of Manu = 10 + 2 = 12 years

Age of Anu = 10 + 4 = 14 years

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