Question

Anu is twice his brother manu if the difference of their ages are 2 years find the age of anu and manu after 10 years.

Answer 1

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Let the present age of manu be x years,

Present age of anu = 2 times of age of manu

                                 = 2x years

Given,if the difference of manu's age and anu's age is 2 years.

∴ manu's age - anu's age = 2 years

⇒ 2x - x = 2

⇒ x = 2  

Therefore present age of anu = x years

                                                    = 2 years    

              present age of manu = 2x years

                                                   = 2( 2 ) years

                                                   = 4 years

Hence, age of anu after 10 years = present age  + 10 years

                                                       = 2 + 10 years

                                                       = 12 years

Age of manu after 10 years = present age + 10 yerars

                                             = 4 + 10 years

                                             = 14 years

Thus,

age of anu after 10 years will be 12 years and age of manu after 10 years will be 14 years.

Answer 2

Given :

Anu is twice as old as her brother Manu .

Difference of their ages is 2 years .

To Find :

Age of Anu and Manu .

Solution :

$\longmapsto\tt{Let\:the\:age\:of\:Manu\:be=x}$

As Given that Anu is twice as old as her brother Manu . So ,

$\longmapsto\tt{Age\:of\:Anu=2x}$

A.T.Q :

$\longmapsto\tt{2x-x=2}$

$\longmapsto\tt\bf{x=2}$

Value of x is 2 .

Therefore :

$\longmapsto\tt{Present\:Age\:of\:Anu=2(2)}$

$\longmapsto\tt\bf{4\:yrs}$

$\longmapsto\tt{Present\:Age\:of\:Manu=x}$

$\longmapsto\tt\bf{2\:yrs}$

After 10 years :

$\longmapsto\tt{Age\:of\:Anu=4+10}$

$\longmapsto\tt\bf{14\:yrs}$

$\longmapsto\tt{Age\:of\:Manu=2+10}$

$\longmapsto\tt\bf{12\:yrs}$