Question

Anu throws two dice once and computes the product of the numbers appearing on the dice aarushi throws 1 die and square is a number that appears on it who has the better chance of getting the number 36​

Answer 1

Anu throws two dice once.

So, total number of outcomes, n(S)=36.

Number of outcomes for getting product 36.

n(E1)=1(6×6)

∴Probability of Anu=n(S)n(E1)=361

Also, Aarushi throw one die.

So, the total number of outcomes n(S)=6

Number of outcomes for getting square of a number is 36.

n(E2)=1(∵62=36)

∴Probability for Aarushi=n(S)n(E2)=61=366

Hence, Aarushi has better chance of getting the number 36.