Anuj has deposited certain amount in the bank to earn compound interest at 10% annum. The difference in the interest on the amount between the 3rd and 2nd year is₹1100 what the amount Anuj deposited?
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Answered by
13
Let the P be x
Therefore c.i for 2nd year= x{(1 + 10/100)^2 -1}
= x{( 11/10)^2 - 1}
= x{ 121/100 - 1}
= x × 21/ 100
= 21x/100
Again,c.i for the 3rd year= x{( 1 + 10/100)^3 -1}
= x{( 11/ 10)^3 -1}
= x { 1331/1000 -1}
= x × 331/ 1000
= 331x / 1000
From the condition we get,
331x/1000 - 21x/100 = 1100
=> 121x/ 1000 = 1100
=> x = 1100000/ 121 = 100000/ 11 = ₹9090.91 (approx)
Therefore the required principal amount is ₹9090.91 (approx)
Therefore c.i for 2nd year= x{(1 + 10/100)^2 -1}
= x{( 11/10)^2 - 1}
= x{ 121/100 - 1}
= x × 21/ 100
= 21x/100
Again,c.i for the 3rd year= x{( 1 + 10/100)^3 -1}
= x{( 11/ 10)^3 -1}
= x { 1331/1000 -1}
= x × 331/ 1000
= 331x / 1000
From the condition we get,
331x/1000 - 21x/100 = 1100
=> 121x/ 1000 = 1100
=> x = 1100000/ 121 = 100000/ 11 = ₹9090.91 (approx)
Therefore the required principal amount is ₹9090.91 (approx)
Answered by
0
Answer:
ans 11000
Step-by-step explanation:
thankyou for asking
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