Question

anuj , salim , and deepak had dinner together in a restaurent . Anuj paid 1/3 of the cost . salim had enough money to pay 1/6 of the bill . deepak paid the remaining . if the bill for the dinner was Rs 240 , how much did each pay​

Answer 1

Answer:

anuj paid 1/3=  1/3*240=rs 80

salim paid1/6=  1/6*240=rs 40

deepak paid the rest =240-(80+40)=rs 120

ans=rs 120

Step-by-step explanation:

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