anuj takes 20 minutes to go to school and 15 minutes to come back from school by his bicycle. if his school is at a distance of 4.5km from his home find his average speed.
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Answer:
2m/s
Step-by-step explanation:
20min = 1200 s
15 min= 900s
S = d/t
4500/2100
= 2m/s
Answered by
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the average speed of Anuj to go to school =4500/1200
=3.75 m/s
the average speed of Anuj to come back from school
=4500/900
=5 m/s
=3.75 m/s
the average speed of Anuj to come back from school
=4500/900
=5 m/s
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