Anuja borrowed Rs 3150 from a moneylender at 6% p.a. simple interest. After one year, she paid back Rs 2339. How much should she pay to clear off the debt at the end of the 2nd year.
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Answers
Answered by
27
P=3150
R=6%p.a.
T=2yr
But after 1 year she paid back ₹2339
So
Si of 1st year
Si=pxrxt /100
Si=3150x6x1/100
Si=189
So paid back 2339
From 3150+189=₹3339
AMOUNT still to be paid =3339-2339=1000
Then
Si=1000x6x1/100
Si=60
Amount =1000+60
=₹1060
She can clear off by paying 1060 at the end of 2nd year
This is ur ans hope it will help you in case of any doubt comment below
R=6%p.a.
T=2yr
But after 1 year she paid back ₹2339
So
Si of 1st year
Si=pxrxt /100
Si=3150x6x1/100
Si=189
So paid back 2339
From 3150+189=₹3339
AMOUNT still to be paid =3339-2339=1000
Then
Si=1000x6x1/100
Si=60
Amount =1000+60
=₹1060
She can clear off by paying 1060 at the end of 2nd year
This is ur ans hope it will help you in case of any doubt comment below
Faiqa93:
thanks a lot!!
Answered by
5
Answer:
1060₹
step by step explanation :
simple interest =
3150×6×1 189 --------------- = ---------- = 189
100 1
amount = simple interest + principal
= 189 + 3150
= 3339₹
principal =amount - simple interest
= 3339 - 2339
= 1000₹
simple interest =
1000×6×1 60 --------------- = ---------- = 60
100 1
amount = simple interest + principal
= 1000 + 60
= 1060₹
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