Math, asked by zarahadiya, 5 days ago

Anusha deposits Rs.10500 in a bank and receives Rs 150 interest. What sum of
money should he deposit in order to get Rs 900, if rate of interest and the time of
deposit are the same?

Answers

Answered by vishalns1994
0

Answer:

sum of money should he deposit in order to get Rs 900 is 63000 Rs

Step-by-step explanation:

Given : Deposit amount  P1= 10500 Rs

            Interest received I1= 150 Rs

           To get I2 - Rs 900 as interest, Deposit = P2

           R1 = R2 = R and T1=T2=T

Solution : Rate of interest and the time of deposit are the same in both

                cases

I₁ = P₁TR/100 -----------1          and                  I₂ = P₂TR/100 -----------2

1 divided by 2 gives

I₁/I₂ = P₁/P₂

P₂ = P₁ x I₂/ I₁

                   P₂ = 10500 x 900/150

                      = 10500 x 6

                      = 63000 Rs

Answered by Anonymous
0

Given - Original and new principal and original interest

Find - New interest

Solution - Sum of Rupees 63,000 will give the interest of Rupees 900.

The formula of Simple Interest is -

S.I. = P*T*R/100. In this formula, P is principal, R is rate of interest and T is time.

As rate of interest and time are same, on comparing the two equations, these two values will be cancelled along with number 100.

So, the new equation will be -

 \frac{i1}{i2}  =  \frac{p1}{p2}

Keeping the values in equation to find the value of new principal.

 \frac{150}{900}  =  \frac{10500}{p2}

P2 = 10500*150/900

p2 =  \frac{10500 \times 900}{150}

P2 = 63,000

Thus, sum of Rupees 63,000 will give the interest of Rupees 900.

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