Anvar saves some amount every month. In first three months he saves ` 200, . 250 and ` 300 respectively. Inwhich month will he save 1000?
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Solution: Saving in first month ` 200; Saving in second month ` 250; ..... 200, 250, 300, . . . this is an A.P. Here a = 200, d = 50, Let’s find n using t
n formula and then find Sn
: tn = a+(n-1)d
= 200 +(n-1)50
= 200 + 50n - 50
1000 = 150 + 50n
150 + 50n = 1000
50n = 1000 - 150
50n = 850
:n = 17
In the 17th month he will save ` 1000.
Let’s find that in 17 months how much total amount is saved.
Sn= n2 [2a+(n-1)d]
= 172 [2 ´ 200+(17-1) ´ 50]
= 172 [400 + 800]
= 172 [1200]
= 17 x600
= 10200
:In 17 months total saving is 10200.
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