Anwer for 20 points. A basketball team won two out of their last four games. In how many different orders could they have two wins and two losses in four games?
Answers
Answer:
instead of 6 choose 4, you really only have 5 choose 3, or (5!)/(3!2!) = (5x4)/2 =10.
So it depends on whether or not the last game needs to be a win. If we are talking the last six games of the regular season, then Mr. Rutter is correct.
Step-by-step explanation:
: A basketball team won two out of their last four games. In how many different orders could they have two wins and two losses in the four games?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A basketball team won two out of their last four games. In how many different orders could they have two wins and two losses in the four games?
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The is number of ways to arrange aabb where a=win and b=lose
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# of arrangements = 4!/(2!*2!) = 24/4 = 6