Question

anwer the question step by step​

Answer 1

ANSWER

considering thita = A

sin A = P/H (P= perpendicular , H= hypotenuse , B = base)

P= p

H= q

B^2=H^2 - P^2 ( pythagoras theorem)

by solving this we get

B = under root p^2 - q^2

according to question we have to find cosA + sinA ,and cos A = B/H , so

cosA + sinA= B/H+ P/H

= under root/ q + p/q

[taking L.C.M we get a as common]

under root p^2 -q^2 + p /q

your answer is under root p^2-q^2 + p/q

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