anwer the question step by step
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considering thita = A
sin A = P/H (P= perpendicular , H= hypotenuse , B = base)
P= p
H= q
B^2=H^2 - P^2 ( pythagoras theorem)
by solving this we get
B = under root p^2 - q^2
according to question we have to find cosA + sinA ,and cos A = B/H , so
cosA + sinA= B/H+ P/H
= under root/ q + p/q
[taking L.C.M we get a as common]
under root p^2 -q^2 + p /q
your answer is under root p^2-q^2 + p/q
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