Question

Anwer the questions
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Answer 1

1 . Area = 25 cm²

2. Answer:

Answer:Area of one wall =lengthxheight=5x8=40 sq.m

Answer:Area of one wall =lengthxheight=5x8=40 sq.mArea of another adjacent wall

Answer:Area of one wall =lengthxheight=5x8=40 sq.mArea of another adjacent wall=widthxheight=3x8=24 sq.m

Answer:Area of one wall =lengthxheight=5x8=40 sq.mArea of another adjacent wall=widthxheight=3x8=24 sq.mArea of 4 walls

Answer:Area of one wall =lengthxheight=5x8=40 sq.mArea of another adjacent wall=widthxheight=3x8=24 sq.mArea of 4 walls=2×40+24×2-4.5-2.25-128-6.75-121.25

Answer:Area of one wall =lengthxheight=5x8=40 sq.mArea of another adjacent wall=widthxheight=3x8=24 sq.mArea of 4 walls=2×40+24×2-4.5-2.25-128-6.75-121.2573.0

Answer:Area of one wall =lengthxheight=5x8=40 sq.mArea of another adjacent wall=widthxheight=3x8=24 sq.mArea of 4 walls=2×40+24×2-4.5-2.25-128-6.75-121.2573.0Cost of painting the four walls

Answer:Area of one wall =lengthxheight=5x8=40 sq.mArea of another adjacent wall=widthxheight=3x8=24 sq.mArea of 4 walls=2×40+24×2-4.5-2.25-128-6.75-121.2573.0Cost of painting the four walls=121.25×25=3,031.25 Rs.

I HOPE THIS HELPS :)

Answer 2

1) Perimeter of square =20cm

∴4a=20

a=5

$\bold{area \: of \: square =a^2}$

$\bold{=5^2}$

$\bold{=25 \: cm^2}$

2) Area of one wall =length-height=5x8=40 sq.m

Area of another adjacent wall =widthxheight=3x8=24 sq.m

Area of 4 walls

=2×40+24×2-4.5-2.25-128-6.75-121.25

Cost of painting the four walls

= 121.25×25-3,031.25 Rs.