anwer this image please
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a=7-4root3
let square root of 7-4root3 = rootx-rooty
squaring both the side we get
7-4root3=x+y-2rootxy
so
x+y=7
2rootxy=4root3
rootxy=2root3
again squaring both the side we get
xy=12
(x+y)^2=x^2+y^2+2xy
49=x^2+y^2+24
x^2+y^2=25
(x-y)^2=x^2+y^2-2xy
(x-y)^2=25-24
(x-y)^2=1
(x-y)=1
by adding equations 1&2 we get
2x=8
x=4
y=3
square root of 7-4root3 = 2-root3
so roota+1/roota
=2-root3+1/2-root3
=2-root3+2 +root3
=4
so your answer is 4
let square root of 7-4root3 = rootx-rooty
squaring both the side we get
7-4root3=x+y-2rootxy
so
x+y=7
2rootxy=4root3
rootxy=2root3
again squaring both the side we get
xy=12
(x+y)^2=x^2+y^2+2xy
49=x^2+y^2+24
x^2+y^2=25
(x-y)^2=x^2+y^2-2xy
(x-y)^2=25-24
(x-y)^2=1
(x-y)=1
by adding equations 1&2 we get
2x=8
x=4
y=3
square root of 7-4root3 = 2-root3
so roota+1/roota
=2-root3+1/2-root3
=2-root3+2 +root3
=4
so your answer is 4
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